0=-26t^2+29t+6

Solution for 0=-26t^2+29t+6 equation:

0=-26t^2+29t+6

We move all terms to the left:

0-(-26t^2+29t+6)=0

We add all the numbers together, and all the variables

-(-26t^2+29t+6)=0

We get rid of parentheses

26t^2-29t-6=0

a = 26; b = -29; c = -6;
Δ = b2-4ac
Δ = -292-4·26·(-6)
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1465}}{2*26}=\frac{29-\sqrt{1465}}{52}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1465}}{2*26}=\frac{29+\sqrt{1465}}{52}
$